-r^2-4r(3r+3)=

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Solution for -r^2-4r(3r+3)= equation:


Simplifying
-1r2 + -4r(3r + 3) = 0

Reorder the terms:
-1r2 + -4r(3 + 3r) = 0
-1r2 + (3 * -4r + 3r * -4r) = 0
-1r2 + (-12r + -12r2) = 0

Reorder the terms:
-12r + -1r2 + -12r2 = 0

Combine like terms: -1r2 + -12r2 = -13r2
-12r + -13r2 = 0

Solving
-12r + -13r2 = 0

Solving for variable 'r'.

Factor out the Greatest Common Factor (GCF), '-1r'.
-1r(12 + 13r) = 0

Ignore the factor -1.

Subproblem 1

Set the factor 'r' equal to zero and attempt to solve: Simplifying r = 0 Solving r = 0 Move all terms containing r to the left, all other terms to the right. Simplifying r = 0

Subproblem 2

Set the factor '(12 + 13r)' equal to zero and attempt to solve: Simplifying 12 + 13r = 0 Solving 12 + 13r = 0 Move all terms containing r to the left, all other terms to the right. Add '-12' to each side of the equation. 12 + -12 + 13r = 0 + -12 Combine like terms: 12 + -12 = 0 0 + 13r = 0 + -12 13r = 0 + -12 Combine like terms: 0 + -12 = -12 13r = -12 Divide each side by '13'. r = -0.9230769231 Simplifying r = -0.9230769231

Solution

r = {0, -0.9230769231}

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